Python regex finditer

Just a revision for me, sharing with you all!
so i have problem to find multiple keywords in a text. i tried using re.search. but that wouldnt work.
as re.search only applicable if keyword found first in a group match.

so, lets go ahead!

i ran using python2.7

Example code for find keywords appearance using python re.finditer (regex)

 search_keywords = ["smart", "high", "confident", "mature"] 

 Now we join the keywords with OR operator | , it will looks something like this
 smart|high|confident|mature

search_patterns = "|".join(search_keywords)

Sample input text

text = "This is a story about a girl. Living in a secluded area in Wonderland.\n" \
       "She is small but very smart and smart, how ever she has verly low confident. Dont judge a book" \
       "by its cover.\n The way she thinks shown how mature she is."

 Now we update the pattern again with ( ) - > parenthesis
 The object is to capture the keyword as a group not individual character. it will looks like
 (smart|high|confident|mature)

search_patterns = "(%s)" % search_patterns
regex = re.compile(search_patterns)

 To find all pattern matches we need to use finditer function. because findall/search will
 only return the first match of the keyword in (smart|high|confident)
 If we use online regex parser,
 we can see that to achieve the same thing we need to apply "Global" flag. Unfortunately python
 doesnt support that.

it = regex.finditer(text, re.MULTILINE)

 To check individual match result, iterate and print m.group()

for match in it: 
    print match.group()

 When you ran, you will get this result

 smart
 smart
 confident
 mature

Try out too!, i did post the note in git. you may refer there